Question

Use log10 (5) ≈ 0.6990 and log10 (7) ≈ 0.8451 to approximate the value of log10 (245) .

Answer 1

hint : 245 = 5 x 49

Answer 2

I got ≈ 2.699

Answer 3

close, check again...

Answer 4

Got the same answer :/

Answer 5

\(\large \log_{10} 245\)

\(\large \log_{10} 5 * 49\)

\(\large \log_{10} 5 + \log_{10} 49\)

\(\large \log_{10} 5 + \log_{10} 7^2\)

\(\large \log_{10} 5 + 2 * \log_{10} 7\)

\(\large 0.6990 + 2*0.8451 \)

\(\large 2.3892\)

Answer 6

log(A*B) = log(A) + log(B)

Answer 7

Oh ok thanks...

Answer 8

np :)