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Simplify. (2²)‾³
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use this :- \(\large a^{-m} = \frac{1}{a^m}\)
lol i dont understand
okay il show you :) \((2^2)^{-3}\)
thats how the given expression is ?
yes
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\(\large (2^2)^{-3}\) first, we get rid of the negative exponent : \(\large \frac{1}{(2^2)^{3}}\)
\(\large \frac{1}{(4)^{3}}\)
\(\large \frac{1}{64}\)
does that makes some sense
Yess but is it neg. or posititve?
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positive oly
a negative exponent becomes positive when u put it over 1
Ohhhhhh ok thank you soo much
np :)
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