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Mathematics 24 Online
OpenStudy (anonymous):

Simplify. (2²)‾³

ganeshie8 (ganeshie8):

use this :- \(\large a^{-m} = \frac{1}{a^m}\)

OpenStudy (anonymous):

lol i dont understand

ganeshie8 (ganeshie8):

okay il show you :) \((2^2)^{-3}\)

ganeshie8 (ganeshie8):

thats how the given expression is ?

OpenStudy (anonymous):

yes

ganeshie8 (ganeshie8):

\(\large (2^2)^{-3}\) first, we get rid of the negative exponent : \(\large \frac{1}{(2^2)^{3}}\)

ganeshie8 (ganeshie8):

\(\large \frac{1}{(4)^{3}}\)

ganeshie8 (ganeshie8):

\(\large \frac{1}{64}\)

ganeshie8 (ganeshie8):

does that makes some sense

OpenStudy (anonymous):

Yess but is it neg. or posititve?

ganeshie8 (ganeshie8):

positive oly

ganeshie8 (ganeshie8):

a negative exponent becomes positive when u put it over 1

OpenStudy (anonymous):

Ohhhhhh ok thank you soo much

ganeshie8 (ganeshie8):

np :)

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