Question

Simplify x - 1
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x^2 + x - 6 x^2 - 6x + 8

Answer 1

is it set equal to zero?

Answer 2

first solve x^2 + x - 6 and x^2 - 6x + 8

Answer 3

\[\frac{x}{x^2+x-6}-\frac{1}{x^2-6 x+8}\]
Factor the denominators

Answer 4

\[\frac{x}{x^2+x-6}-\frac{1}{x^2-6 x+8} \\ \\ =\frac{x}{(x-2)(x+3)}-\frac{1}{(x-4)(x-2)} \]
Then find the common denominator and stick those fractions together

Answer 5

Ok thanks guys