Simplify the expression: -20a ^{-2}b ^{-7} / 5a ^{-5}b ^{3} Write your answer without negative exponents.
\[-20a ^{-2}b ^{-7} / 5a ^{-5}b ^{3}\] There is the equation how it is supposed to look.
$$\frac{-20a ^{-2}b ^{-7}}{ 5a ^{-5}b ^{3}}$$
Yeah, thats the equation. I'm just a little lost.
The first thing you should understand is this is not an "equation," it is an "expression" do you know why?
Because it doesn't have an equals sign to equal a value.
Correct :) An "equation" must have an "equals sign"
So when I'm dividing two numbers like this, don't I divide all whole number and subtract like variables?
There are certain "rules of exponents" that you should understand first. You are perfectly correct in working with "like variables" by this I mean the bases must be the same.
So I can subtract the exponents on say \[a^{-2}\] and \[a ^{-5}\]?
Yes, -3-(-5) is the exponent on a.
But the first A has a negative two on it?
And then that gives us -7, but the question says to write the answer without negative exponents. This is where I start to get lost...
Ooops I meant -2-(-5) is the exponent on a.
Okay so that gives us A^-7, and like I said... the original question asks to write it without negative exponents. I kinda get lost whenever I come to this point.
What is -2-(-5)=?
OH! its a negative negative... so the answer to that would be 3?
Yes :)
Okay, and just one final question. On the -20 / 5... its just that, right? -20 / 5?
Actually one more question now that I look at that. The b^-7 and b^3 would be -7 + 3, correct?
How many times does 5 go into 20?
4
So -20 / 5 =?
-4
Correct :)
Okay, now one more question (sorry). The -7 + 3 on the B's would be -4. What am I not seeing there?
The exponent is 10 on b and it belongs in the denominator.
How?
3-(-7)
Ah okay, so it would be \[-4a ^{3}b ^{10}\]
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