Question

How many x-intercepts does the graph of y = -(x + 1)2 - 2 have?

Answer 1

This graph has one x-intercept, at the point (-2, 0).

Answer 2

I think (x+1)2 is supposed to be \((x+1)^2\) THerefore the graph is like this:

is that right?

Answer 3

By definition of a quadratic equations has two x intercepts

Answer 4

sometimes it has none.

Answer 5

In that case then it would be none but if he has any, its two

Answer 6

or one...

Answer 7

never

Answer 8

\(x^2\) has one intercept I think.

Answer 9

No, it has none because the vertex this is the origin

Answer 10

I see. so it's not just "the roots".

Answer 11

.No, only real roots, when it has no x-intercepts the roots are complex

Answer 12

what I meant is, an intercept is not just a root, because the vertex can be root but can't be intercept, as you told me.

Answer 13

Anyway, the answer to this post is None.