Simplify the expression: \[\left( \frac{ x ^{4}y ^{8} }{ x ^{6}y ^{6}} \right)^{1/2}\] Write your answer without negative exponents.
I'm just gonna be honest here... I look at this expression and cringe in fear. So I'm gonna need help from the ground up.
you can start by dividing each exponent by 2, since everything is being raised to the power of one half
i.e start with \[\frac{x^2y^4}{x^3y^3}\]
then subtract the exponents of the like terms
Okay, then we add the exponents with the same bases?
no, you subtract because it is a fraction (division) if it was multiplication you would add them
Okay, so we get \[x ^{-1}y\]
since you have to write with positive exponents, subtract the smaller ones from the bigger ones
yeah that is right, what you wrote
but as i said, you want positive exponents, so i would think like this \[\large \frac{x^2y^4}{x^3y^3}=\frac{y^{4-3}}{x^{3-2}}=\frac{y}{x}\]
you got the same answer
so its just xy?
no it is what i wrote
Okay.
writing with positive exponents does not mean change the minus signs to plus signs it means use the fact that \(x^{-1}y=\frac{y}{x}\)
notice you could have done the subtractions first, like this \[\left( \frac{ x ^{4}y ^{8} }{ x ^{6}y ^{6}} \right)^{1/2}=\left( \frac{ y ^{2} }{ x ^{2}} \right)^{1/2}\] then divided the exponents by 2 either way works,whatever you think is easiest
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