Question

Check my work please...

\[\frac{ -10a ^{-4}b ^{-1} }{ 5a ^{-2}b ^{8} }\]

Answer 1

-10 / 5 = -2

\[a ^{\left( -4 - (-2) \right)} = a ^{-2}\]

\[b ^{\left( -1 - 8 \right)} = b ^{-9}\]

Answer 2

Now how do I get the exponents to be positive in the final answer... here is the original question:

Simplify the expression:

\[\frac{ 10a ^{-4}b ^{-1} }{ 5a ^{-2}b ^{8} }\]

Write your answer without negative exponents.

Answer 3

@anyone

Answer 4

\[ -2 a^{-2}b^{-9} \]
to change the sign of the exponent, "flip" the base... if up top, put it in the bottom or vice versa

Answer 5

so you get -2 over the other stuff

Answer 6

So \[\frac{ -2 }{ a ^{2}b ^{9}}\]

Answer 7

???

Answer 8

yes, that is right.

Answer 9

Awsome, thanks for your help!