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Geometry 53 Online
OpenStudy (anonymous):

The figure below shows CB = 4, BE = 5, AB = x - 4, and DB = x + 3.

OpenStudy (anonymous):

OpenStudy (anonymous):

If △ABC ~ △DBE, the value of x is _________

OpenStudy (amistre64):

is that similar or congruent?

OpenStudy (anonymous):

similar

OpenStudy (amistre64):

yeah, i see that like edges are 4 and 5 so, since they are similar they differ my some multiple "m"; such that: 4m = 5 ... what is the value of the multipler?

OpenStudy (amistre64):

the like sides to then compare are: m(x+3) = x-4

OpenStudy (anonymous):

hmmmmm so i divide 5 by 4 correct?

OpenStudy (anonymous):

thats 0.8 correct?

OpenStudy (amistre64):

or possible the other way around ... x+3 = m(x-4)

OpenStudy (anonymous):

so then 0.8(x+3)=x-4

OpenStudy (anonymous):

0.8x + 2.4 = x-4

OpenStudy (anonymous):

subtract 2.4 from both sides and you have 0.8x = x-6.4

OpenStudy (anonymous):

@armistre

OpenStudy (anonymous):

@armistre64

OpenStudy (amistre64):

the "little" triangle is multipled by m to equal the bigger one m(little) = big m(x-4) = x+3 i had the triangles backwards at first

OpenStudy (amistre64):

mx - 4m = x+3 mx -x = 4m+3 x(m -1) =4m+3 x = (4m+3)/(m-1)

OpenStudy (anonymous):

so what is M? 0.8?

OpenStudy (amistre64):

since 4m = 5, m = 5/4 is going to be greater than .8

OpenStudy (anonymous):

ok so where do I go now? haha

OpenStudy (anonymous):

If m is 5/4 then you plug that into what equation?

OpenStudy (amistre64):

yes

OpenStudy (amistre64):

x = (4m-3)/(m-1)

OpenStudy (amistre64):

err.. +3. my fingers hate me

OpenStudy (anonymous):

and M is 0.8 or 5/4?

OpenStudy (amistre64):

that has already been addressed in the postings .....

OpenStudy (anonymous):

so according to your post m = 0.8 So... we plug that in to get.... (giveme a sec)

OpenStudy (amistre64):

since 4m = 5, m = 5/4 is going to be greater than .8

OpenStudy (anonymous):

so X= 2/0.25?

OpenStudy (amistre64):

more like [4(5/4)+3] / [5/4 - 4/4] [5+3] / [1/4] 8/ [.25]

OpenStudy (anonymous):

oh ok so I plug that in for X?

OpenStudy (amistre64):

yes, that will be the value of x

OpenStudy (amistre64):

you might need to reduce it more to be formated correctly

OpenStudy (anonymous):

ok and I plug it into what equation? and I plug it in as 32

OpenStudy (amistre64):

since the end goal was to determine a value for x, and we found that x = 32 .... there is nothing left to do with the problem

OpenStudy (anonymous):

oh ok thanks so much! i hate final exams lol

OpenStudy (amistre64):

youre welcome

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