The figure below shows a parallelogram ABCD. The flow chart with missing reason proves that consecutive angles of a parallelogram add to 180°. Which reason can be used to fill in the blank spaces? a) Angle Addition Postulate b) Definition of a Quadrilateral c) Definition of Parallel Lines d) Definition of a Parallelogram
@ganeshie8
This would be definition of parallel lines, right?
more approppriate here is this :- d) Definition of a Parallelogram
Okay, thank you! What about this one: The figure below shows rectangle ABCD. The two-column proof with missing statement proves that the diagonals of the rectangle bisect each other. Which statement can be used to fill in the blank space? a) AB ≅ CD b) BE ≅ AE c) BE ≅ CE d) BC ≅ AD
after blank, look at the next second step
Alternate interior angles theorem?
there we're using ASA to prove congrence
next to that step
Oh that step, okay.
look at those two triangles :- \(\triangle ADE\) and \(\triangle CBE\)
BC = AD , by definition of parallelogram.
Got it, because the two sides are the same length - that makes sense!
yes ! opposite sides (BC and AD) are equal in a parallelogram
Thank you!! Answer Choices (the question is the picture): ∡1 + ∡2 = ∡3 + ∡4 ∡1 + ∡2 = 180 and ∡2 + ∡3 = 180 ∡1 + ∡2 = ∡2 + ∡3 ∡1 = ∡3
I have no idea how to do this, I don't even know where to start with this one
@ganeshie8
easy, just subtract \(\angle 2 \) both sides
so the last choice angle 1 = angle 3
Yes !
Thank you! Okay, how do I prove that the diagonals of the square bisect the interior angles of the figure attached?
easy, prove \(\triangle PQR \cong \triangle PSR\)
hold on, you wanto prove diagonals bisect the angles... let me think a bit
discard above
Okay, is there like a specific theorem or postulate we can use?
do this :- 1. prove \(\triangle PQT \cong \triangle RQT\) 2. then, by CPCTC, \(\angle PQT \cong \angle RQT\)
for 1, you can use SSS congruence. i need to go cya in an hour or so. good luck !
Okay, thank you!
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