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Mathematics 13 Online
OpenStudy (anonymous):

The figure below shows a parallelogram ABCD. The flow chart with missing reason proves that consecutive angles of a parallelogram add to 180°. Which reason can be used to fill in the blank spaces? a) Angle Addition Postulate b) Definition of a Quadrilateral c) Definition of Parallel Lines d) Definition of a Parallelogram

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

This would be definition of parallel lines, right?

ganeshie8 (ganeshie8):

more approppriate here is this :- d) Definition of a Parallelogram

OpenStudy (anonymous):

Okay, thank you! What about this one: The figure below shows rectangle ABCD. The two-column proof with missing statement proves that the diagonals of the rectangle bisect each other. Which statement can be used to fill in the blank space? a) AB ≅ CD b) BE ≅ AE c) BE ≅ CE d) BC ≅ AD

OpenStudy (anonymous):

ganeshie8 (ganeshie8):

after blank, look at the next second step

OpenStudy (anonymous):

Alternate interior angles theorem?

ganeshie8 (ganeshie8):

there we're using ASA to prove congrence

ganeshie8 (ganeshie8):

next to that step

OpenStudy (anonymous):

Oh that step, okay.

ganeshie8 (ganeshie8):

look at those two triangles :- \(\triangle ADE\) and \(\triangle CBE\)

ganeshie8 (ganeshie8):

BC = AD , by definition of parallelogram.

OpenStudy (anonymous):

Got it, because the two sides are the same length - that makes sense!

ganeshie8 (ganeshie8):

yes ! opposite sides (BC and AD) are equal in a parallelogram

OpenStudy (anonymous):

Thank you!! Answer Choices (the question is the picture): ∡1 + ∡2 = ∡3 + ∡4 ∡1 + ∡2 = 180 and ∡2 + ∡3 = 180 ∡1 + ∡2 = ∡2 + ∡3 ∡1 = ∡3

OpenStudy (anonymous):

I have no idea how to do this, I don't even know where to start with this one

OpenStudy (anonymous):

@ganeshie8

ganeshie8 (ganeshie8):

easy, just subtract \(\angle 2 \) both sides

OpenStudy (anonymous):

so the last choice angle 1 = angle 3

ganeshie8 (ganeshie8):

Yes !

OpenStudy (anonymous):

Thank you! Okay, how do I prove that the diagonals of the square bisect the interior angles of the figure attached?

ganeshie8 (ganeshie8):

easy, prove \(\triangle PQR \cong \triangle PSR\)

ganeshie8 (ganeshie8):

hold on, you wanto prove diagonals bisect the angles... let me think a bit

ganeshie8 (ganeshie8):

discard above

OpenStudy (anonymous):

Okay, is there like a specific theorem or postulate we can use?

ganeshie8 (ganeshie8):

do this :- 1. prove \(\triangle PQT \cong \triangle RQT\) 2. then, by CPCTC, \(\angle PQT \cong \angle RQT\)

ganeshie8 (ganeshie8):

for 1, you can use SSS congruence. i need to go cya in an hour or so. good luck !

OpenStudy (anonymous):

Okay, thank you!

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