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Why does the following reaction occur when Ba(OH)2 is not good soluble? Both reactants need to be good soluble for the reaction to occur. Ba(OH)2 + CuSO4 --> Cu(OH)2 (precipitate) + BaSO4 (precipitate) Thanks!
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In my table it says that all hydroxides are not good soluble only NaOH an KOH are good soluble. But I googled the solublity of Ba(OH)2 and see its 1.67 g/100 mL (0 °C) , well i guess that is still right according to the table, but you would have to add not more than 1.67g of both reactants in a solution of 100ml for the reaction to complete, am I right?
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