Question

The graph of which equation is shown below?

Answer 1

y = −x^2 + 2x − 3

y = −x^2 − 2x − 3

y = x^2 + 2x − 3

y = x^2 − 2x − 3

Answer 2

@Notamathgenius

Answer 3

the first answer choice
The roots of the equation are found anywhere the equation y=x^2-2x-3 is equal to zero, like the question states. To do this you must first factor the equation. x^2 is easy enough, it splits into two x's, so you start with:

(x )(x )

Now you have to find the combinations that multiply to give -3 and who's sum is -3. We can use +1 and -3, giving us:

(x+1)(x-3) = 0

We can make the equation equal to zero by making either of two brackets equal to zero, so the equation's roots lie at x=-1 and x=3.