Double integral of D of ln(1+x squared+y squared dxdy, D:x squared +y squared =e squared , y=x√3, x=y√3, x≥0. how do i get the t and the r from the polar coordinates :-S
im not sure what y =xsqrt3 and x=ysqrt3 refer to ?? seems to me the limits are defined by the half circle with radius "e" where x>0
well yes, in polar coordinates, my r+[0,e] and t=[pi/6;pi/3] but i don't have any clue from where to obtain the values of t, t beeing the angle
can i send you the problem ? it's in romanian but i think you can manage, so in this way you will see it on paper.
ok , im not great at polar coord :{ it seems t would range from -pi to pi right ?
sorry i meant -pi/2 to pi/2
the problem is it ranges from pi/6 and pi/3
the second c is the solution, i really don't have any idea from where he gets it :-S
ok those angles come from where the 2 lines intersect the circle y=sqrt3 x , has slope of sqrt3 --> tan(t) = sqrt3 --> t = pi/3 y = x/sqrt3 has slope of 1/sqrt3 --> tan(t) = 1/sqrt3 --> t = pi/6
thx a lot, now i have to get back to 11 th grade and 12 th grade to recall the slope if i remember correctly :D i really appreciate the help
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