Question

Help !

Answer 1

\(y=ax+b\).
the value of \(b\) tells you where the line crosses the y-axis. (when x=0, y = b)
therefore the answer to the first question is NOT 1), neither 4). see that?

Answer 2

Yes

Answer 3

what is the slope of \(y=\frac13x-4\) ?

Answer 4

c?

Answer 5

c is the correct answer

Answer 6

oh ok.

Answer 7

can you please help me on the next one?

Answer 8

11. ? it's just the same technique.

Answer 9

use \(b\), then use \(a\).

Answer 10

can you show me how to use b and a

Answer 11

\(y=-2x+3\). so \(a=-2\) (the slope) and \(b=3\).
Therefore
1) the line crosses the y-axis at y=3. -> (a) or (c)
2) the slope is -2. -> (c).
Only one line fits the above conditions.

Answer 12

can you show me how on the next one?

Answer 13

look, one way to see the slope is to count the little squares.
example: going 3 squares on the left will make the line go 1 square up.
since slope is \(\frac{\Delta y}{\Delta x}\), that means that this line has a slope of 1/3.

in your table, you see that "going 1 to the left" will increase the value of y by .... ?

Answer 14

is this number 12?

Answer 15

no.
x=1, -> y =9
x=2 -> y=12
so \(\Delta y = 3\) when \(\Delta x=1\).

Answer 16

ok.

Answer 17

hold on.

Answer 18

the slope is 3.
now, x=0, what is y? just remove the \(\Delta y\) once from the previous y-value.
9 - 3 = 6.