Question

help please!

Answer 1

\[ 8 = 2^{x+4} \]

Answer 2

x = –4

x = –1

x = 0

x = 7

Answer 3

take log of both sides to start (this will let us get "x" out of the exponent)
\[\ln 8 = \ln (2^{x+4})\]
\[\ln 8 = (x+4) \ln 2\]
\[x+4 = \frac{\ln 8}{\ln 2}\]
\[x = \frac{\ln 8}{\ln 2} - 4\]

Answer 4

thank you :) can you help with aaother one please?

Answer 5

sure

Answer 6

\[(\sqrt{6})^{8x} = 216^{x-3}\]

Answer 7

you could do log of both sides here but there is easier way because 216 is power of 6
rule: if bases are equal, then you can set exponents equal
\[\large (6^{1/2})^{8x} = (6^{3})^{x-3}\]
\[\rightarrow 4x = 3(x-3)\]
you can solve from there

Answer 8

is it-9?

Answer 9

ahh yes

Answer 10

awesome! thanks for your help :)

Answer 11

yw:)