Question

help?!?

Answer 1

@Jhannybean

Answer 2

I have never gotten to series in calculus Lala, sorry.. but I called someone better for you :)

Answer 3

In a geometric series, the series will converge if \[\large |r|<1\]In this case, \[|-\frac{1}{2}| <1 \implies \frac{1}{2}< 1\] therefore the \[\large \sum_{n-1}^{\infty}-4(-\frac{1}{2})^{n-1} = C\]

Answer 4

thank you @Luigi0210

Answer 5

Because it converges, your sum : \[\large S=\frac{a}{1-r}\] where \[\large r=-\frac{1}{2}\]

Answer 6

that stuff looks so familiar >.<

Answer 7

TRue that

Answer 8

so that is the answer?

Answer 9

yes

Answer 10

oh ok!

Answer 11

thanks

Answer 12

you think you could help with another?