Question

help?

Answer 1

yes

Answer 2

whats your question ?

Answer 3

@tcarroll010

Answer 4

think you can help?

Answer 5

Since you want to consider 2 consecutive EVEN integers, you conceive of the first one as:

2x and the next one as 2x + 2

The multiplier of 2 guarantees that it will be even:

1/(2x) + 1/(2x + 2) = 9/40

Answer 6

1/x + 1/(x + 1) = 9/20

[(x + 1) + x] / [x(x + 1)] = 9/20

40x + 20 = 9x^2 + 9x

9x^2 - 31x - 20 = 0

x = 4 -> so 2x = 8 and the next # is 10

1/8 + 1/10 = 9/40

Answer 7

im kinda confused as to what ll of this means

Answer 8

*all

Answer 9

You're looking for 2 consecutive even numbers such that 1 over the first number plus 1 over the second number = 9/40

Those 2 numbers are 8 and 10 because:

1/8 + 1/10 = 9/40

And the equation is set up with the first number being represented as:

2x and the second # is then 2x + 2

The "2" will guarantee that your eventual numbers are even. So you start with that, go to the equation I set up, and solve for "x". Then you take 2x for the first # and 2x + 2 for the second #.

Answer 10

You don't have to find anything. The problem is started and finished. The first number is 8 and the second number is 10.

Answer 11

The reciprocal of 8 is 1/8

The reciprocal of 10 is 1/10

1/8 + 1/10 = 9/40

The 2 numbers that answer the question are 8 and 10.

Answer 12

I hope that you are finding that this is making sense because the problem is done and the explanation is given in detail.

All good now, @lala2 ?

Answer 13

Well, the answer is in 2 parts. You need the initial equation and then you need:

8 and 10.

Answer 14

uw!

Answer 15

Actually, the equation is:

1/(2x) + 1/(2x + 2) = 9/40

Answer 16

The problem is asking for an equation than can be used to find the 2 numbers. So, the equation has to have a variable in it.

Answer 17

oh ok!

Answer 18

I suggest you go over all the logic here. It might help.

Answer 19

yeah that's what im doing!

Answer 20

ok, well thx for the recognition and have a great day.