Question

acceleration due to gravity is -32 ft/s2. a ball is thrown upwards from the surface of the earth with an initial velocity of 16 ft/s. what is its velocity when it hits the ground.

Answer 1

v(t) = a*t +vo

Answer 2

x(t)= 1/2 a t^2 +vo *t + xo

Answer 3

a- acceleration
vo- initial velocity
xo- initial height

Answer 4

t- time

Answer 5

surface would mean xo = 0
initial velocity has been defined as 16 ft/s
and acceleration of gravity is given by -32 ft/s^2

Answer 6

first determine the time when the ball hits the ground

that means x(t) =0
so solve for t

once you've determined the time the ball hits the ground,
use the velocity equation (1st equation) to determine the speed at which it hits the ground

Answer 7

this is the general way to solve the problem

there are much easier and much quicker ways to solve it,
such as using conservation of energy

Answer 8

can u tell me whether the value will be t=1 or not?

Answer 9

@completeidiot

Answer 10

looks like it

Answer 11

velocity = -16?

Answer 12

yup

it hits the ground at the same speed it left the ground

Answer 13

thanks for your help.