Question

how do i factor each polynomial in 30b^2+48b-2?

Answer 1

What is the common multiple in 30, 48 and 2?

Answer 2

hint: \(\large \color{green}{30}b^2+\color{green}{48}b-\color{green}2\)

Answer 3

2

Answer 4

goood job :D

Answer 5

Is that what you were looking for?

Answer 6

what do i do next?

Answer 7

so now you'll factor out a two and see what multiplies to 2 to get your original equation, \[\large 2(?b^2+?b-1)\]

Answer 8

2(15b^2+24b-1)

Answer 9

?

Answer 10

yes, good job. i forgot to mention that instead of factoring out a b, we could have divided everything by 2 also... So let's also try that,

what would you do if you had \[\large \frac{30b^2}{2}+\frac{48b}{2}-\frac{2}{2}\]

(it's just easier to solve i guess)

Answer 11

what about w^5+4w^4+10w^3+40w^2

Answer 12

what is the GCF here? (the w with the smallest power)?

Answer 13

i don't know

Answer 14

hmm... \[\large \color{green}{w^5}+4\color{green}{w^4}+10\color{green}{w^3}+40\color{green}{w^2}\] out of these which w has the smallest exponent?

Answer 15

w2

Answer 16

good job, how you can divide everything by w^2

Answer 17

i dont know

Answer 18

\[\large \frac{w^5}{w^2}+\frac{4w^4}{w^2}+\frac{10w^3}{w^2}+\frac{40w^2}{w^2}\]

Answer 19

is that all i do?