If the two triangles are similar, solve for x http://roads.advancedacademics.com/contentserver/content/roadssection/292201//given%20the%20two%20triangles%20are%20similar%202.gif A. x = 3 B. x = 6 C. x = 9 D. x = 12
the two triangles are similar, so the corresponding sides form a ratio
which means we can say (x+9)/7 = (x+6)/6 cross multiply to get 6(x+9) = 7(x+6) then distribute to get 6x + 54 = 7x + 42 I'll let you finish up
what do i do?
from here you just need to isolate x
6x + 54 = 7x + 42 6x + 54 - 54 = 7x + 42 - 54 6x = 7x - 12 ... ... ... x = ???
i dont know how to finish that :/
are you familiar with solving linear equations?
not really no
alright, what you want to do is move the 7x over so you need to undo adding 7x so you do what?
i learned them but never quite got them
how do we undo +7x
make it negative?
close, you subtract 7x from both sides
6x - 7x = 7x - 12 - 7x notice how the 7x - 7x on the right side will become 0x or just 0
so now its 6x - 12 ?
what is 6x - 7x simplify to
1x? or -1x? im really bad at math
6x - 7x is -1x
so we now have -1x = -12
if -1x = -12 then x = ??
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