what is the intergration of cos x
sin x
thanks
\[\large \int\limits \cos(x)dx = \sin(x) + \color{red}c\]
actually tabkatta and Jhannybean. This lectures disagrees with u . says the intergral of cos x= -sin x. but the derivitve of cos x its -sin x. please watch the link http://www.mathtutor.ac.uk/integration/integrationbyparts/video
\[\large \frac{d}{dx}(\sin(x))= \cos(x) \therefore \int\limits \cos(x) = \sin(x) + c\]
uhm integral of cosine is sine...
integral of sine is negative cosine
thanks a lot guys you are perfectly right
and thanks for the link
so what is the intergral of sine x?
-Cos
why - cos x?
Because Derivative of Cos = -Sin Integral of Sin = Integral of -(-Sin) = Integral of - (Derivative of Cos) = - Integral of Derivative of Cosine = - Cosine
if that makes any sense
\[\large \frac{d}{dx}(\cos(x)) = -\sin (x) \therefore -\int\limits \sin(x)dx= - \cos(x)\]
exactly what @bahrom7893 said, but in equation format.
that. what is the intergral of -cox
and -sin x
just take the negative outside the integral and integrate, add the negative in after.
I just did both of them for you
so it means the intergration of -cos x its -sine x?
thanks im right
yea
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