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Calculus and Vectors: (Step by Step please - I really don't understand this one) Let u = 4i-2j+ 3k and v = [−1, 0, 3]. Determine the following. a. 3u - 2v b. | v| c. directional angles of v d. unit vector of v .
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u =<4,-2,3> and v=<-1,0,3> so 3u =<12,-6,9> and 2v= <-2,0,6> hence 3u-2v = 10,-6,3>
|v|=sqrt( 1+0+9)=sqrt(10)
direction angles of v are cos^-1(-1/sqrt(10)) , 90 degree, cos^-1(-3/sqrt(10)) plz neglect any typo error
unit vector of v = <-1/sqrt(10),0,3/sqrt(10)>
wouldn't the answer be (14,-6,3) for the first one?
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yes its (14,-6,3) , they just had a typo
alright, than kyou
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