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Mathematics 7 Online
OpenStudy (anonymous):

Simplify as far as possible

OpenStudy (anonymous):

\[\frac{ 10^{-7} \times 10^{3}}{10^{2} }\]

OpenStudy (whpalmer4):

Okay, two things to remember: When you have exponents with the same base: \[x^n*x*m = x^{n+m}\] \[\frac{x^n}{x^m} = x^{n-m}\] With those two formulas, you can simplify that to \(10^n\) where \(n\) is some number.

OpenStudy (whpalmer4):

Ackthpht. \[x^n*x^m = x^{n+m}\]

OpenStudy (anonymous):

Ok so the answer is 10^2 thanks for the help whpalmer it is much appreciated!

OpenStudy (whpalmer4):

Oh, it appears I didn't help as much as I could have...that's not the right answer :-( What does \(10^{-7}*10^3 =\)

OpenStudy (anonymous):

ah 10^-3 so the answer is 10^-5?

OpenStudy (whpalmer4):

No guessing, let's get this right. \[10^{-7}*10^{3} = 10^{-7+3} = \]

OpenStudy (whpalmer4):

Identical bases, you just add the exponents...

OpenStudy (whpalmer4):

-7 + 3 =

OpenStudy (anonymous):

my mistake it's -4

OpenStudy (whpalmer4):

Right. Now the division: \[\frac{10^{-4}}{10^2}=\] Identical bases, so we subtract: \[10^{-4-2} = \]

OpenStudy (anonymous):

yep so the answer is 10^-6

OpenStudy (whpalmer4):

Bingo!

OpenStudy (whpalmer4):

Guys named William have to watch out each other, right? :-)

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