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OpenStudy (anonymous):
\[\frac{ 10^{-7} \times 10^{3}}{10^{2} }\]
OpenStudy (whpalmer4):
Okay, two things to remember:
When you have exponents with the same base:
\[x^n*x*m = x^{n+m}\]
\[\frac{x^n}{x^m} = x^{n-m}\]
With those two formulas, you can simplify that to \(10^n\) where \(n\) is some number.
OpenStudy (whpalmer4):
Ackthpht. \[x^n*x^m = x^{n+m}\]
OpenStudy (anonymous):
Ok so the answer is 10^2 thanks for the help whpalmer it is much appreciated!
OpenStudy (whpalmer4):
Oh, it appears I didn't help as much as I could have...that's not the right answer :-(
What does \(10^{-7}*10^3 =\)
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OpenStudy (anonymous):
ah 10^-3 so the answer is 10^-5?
OpenStudy (whpalmer4):
No guessing, let's get this right.
\[10^{-7}*10^{3} = 10^{-7+3} = \]
OpenStudy (whpalmer4):
Identical bases, you just add the exponents...
OpenStudy (whpalmer4):
-7 + 3 =
OpenStudy (anonymous):
my mistake it's -4
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OpenStudy (whpalmer4):
Right. Now the division:
\[\frac{10^{-4}}{10^2}=\]
Identical bases, so we subtract:
\[10^{-4-2} = \]
OpenStudy (anonymous):
yep so the answer is 10^-6
OpenStudy (whpalmer4):
Bingo!
OpenStudy (whpalmer4):
Guys named William have to watch out each other, right? :-)