(3d^2+2d-29) ÷ (d+3)

Question

anonymous · Answer

@Hero :D

anonymous · Answer

Okay, so:
(3d^2+1d^2-29)
...the 29 doesn't factor...

hero · Answer

Now you're changing it. First it was 3d^2 + 2d - 29

anonymous · Answer

I though factoring was:
Heres an example:
example: given
$$y^2-4$$
this could be rewritten as:
$$y^2-2^2$$
and using the fact i gave for factorising difference of two squares,
$$(y+2)(y-2)$$

anonymous · Answer

Hmm?

hero · Answer

That's difference of squares. It's one of several factoring methods. There's no difference of squares in this particular expression.

hero · Answer

If  you can't factor, then just use long division

anonymous · Answer

Oh, ok. So what do I do then? Oh...you just said...

anonymous · Answer

$$3d ^{2}+2d-29\div(d+3)$$

hero · Answer

You need to do long division for this bro

anonymous · Answer

Ok so like:
...Could you help or give an example?

hero · Answer

It's impossible to do long division on this site...without giving answers so, I'll direct you to a resource: http://calc101.com/webMathematica/long-divide.jsp

anonymous · Answer

Oh cool...this shows you all the work thanks :D your my @Hero lol