Question

n -^4 w^0

Answer 1

anything to the 0 power is 1. examples:
2^0 = 1
3^0= 1
a^0 =1

Answer 2

ohhh yeah so like w^0 is 1?

Answer 3

an negative exponent can be changed to a positive exponent using this rule:
\[ x^{-a} = \frac{1}{x^a} \]
and
\[ x^{a} = \frac{1}{x^{-a}} \]

Answer 4

"flip" the number and change the sign of the exponent.

Answer 5

flip what number

Answer 6

is the problem
\[ n^{-4} w^0 \]?

Answer 7

yes

Answer 8

so you know w^0= 1 and you have
\[ n^{-4} \cdot 1 = n^{-4} \]

Answer 9

if you don't want a -4 for the exponent , use this rule:
\[ x^{-a} = \frac{1}{x^a}\]

Answer 10

Do you understand the rule ?

Answer 11

i dont understand the rule but i understand the step before that..

Answer 12

match your problem
\[ n^{-4} \]
with
\[ x^{-a} \]
the "n" goes with the "x" and the 4 goes with the "a"

the rule is
\[ x^{-a} = \frac{1}{x^a}\]

the idea is rewrite your problem so it matches the rule

Answer 13

n^-4 = ?

Answer 14

is there any other way to do this because i know the answer but i just dont understand the steps

Answer 15

what is the answer ?

Answer 16

1/16

Answer 17

do they tell you that n is some number ?

Answer 18

oh yeah n=-2 and w=5

Answer 19

ok, that makes sense.

First, do you know that the little numbers (the exponents) are a "short-hand" people came up with to save typing?

n^3 means n*n*n (n times itself 3 times)
n^1 means n
n^2 means n*n

n^4 means n*n*n*n

n^10 is too much to type out...

does that part make sense ?

Answer 20

yes

Answer 21

next, people decided that n^0 (or anything to the 0 power) is 1
(so your w^0 is 1 in your problem)

then they said: "what about negative exponents?" like \( n^{-1} \) ?
that means it is 1 divided by n^1: \( \frac{1}{n^1} \)

if you see a negative exponent, rewrite the expression by dividing it into 1

\[ x^{-1} = \frac{1}{x^1} \\ x^{-2} = \frac{1}{x^2}\\ x^{-3} = \frac{1}{x^3} \]
and so on

do you follow ?

Answer 22

so, for your problem
\[ n^{-4} w^0 = \frac{w^0}{n^4} \]

Answer 23

as you know w^0 is 1, and n^4 is n*n*n*n, so you can write this as
\[ n^{-4} w^0 = \frac{w^0}{n^4} = \frac{1}{n \cdot n \cdot n\cdot n} \]

Answer 24

to get the number, replace every n with -2 (because n= -2)
\[ \frac{1}{n \cdot n \cdot n\cdot n} = \frac{1}{-2 \cdot -2 \cdot -2\cdot -2} \]

Answer 25

now multiply -2*-2 * -2 *-2 to simplify

Answer 26

16

Answer 27

OOOOOH I GET THANK YOU SO MUCH!!!!

Answer 28

\[ \frac{1}{n \cdot n \cdot n\cdot n} = \frac{1}{-2 \cdot -2 \cdot -2\cdot -2} = \frac{1}{16} \]