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ok i have a little stupid question :-S what is the volume of z^2=X^2+y^2 with z belonging to [0;1] triple integrals :-S
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triple integrals are pretty smart material.......
its not a stupid question at all :), find some solutions of similar problems on the internet so you can get some point how to calculate volume in R3 space
done that, it's just that this one is kind of awkward, i think it should be 2pi/3 but from my calculation that is the only thing that isn't
\[\frac 2 3 \pi\]
woops!! z goes from 0 to 1, it's 1/3 pi
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easy way, |dw:1370446684971:dw| another way calculate this integral \[ \int_{-1}^{1} \int_{-\sqrt{1 - x^2}}^{\sqrt{1 - x^2}}\int_{0}^{\sqrt{x^2 + y^ 2}} dz dy dz\]
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