http://www.wolframalpha.com/input/?i=%288q%5E2%29+%2F+sqrt%28q%5E17%29+ @ParthKohli how do i check this answer? lol

Question

parthkohli · Answer

Look at "alternate form assume q is positive"

gabylovesyou · Answer

but since its a fraction how do i simplify it more ?

parthkohli · Answer

You cannot simplify fractions. And BTW, what answer do you get?

parthkohli · Answer

You should have an answer for yourself before looking at one on Wolfram.

hartnn · Answer

$\large \dfrac{8}{\sqrt{q^{13}}}, 8q^{-13/2}$
are different forms of that same answer...

parthkohli · Answer

If you need help with it,$$\dfrac{8q^2}{\sqrt{q^{17}}} = \dfrac{8q^2}{q^{\frac{17}{2}}}$$

gabylovesyou · Answer

my answer was 8 sqrt(q) / (q^7)

hartnn · Answer

thats correct!

parthkohli · Answer

Indeed.

hartnn · Answer

8/q^(13/2) = 8 sqrt(q) / (q^7)

gabylovesyou · Answer

ok thanks :p

gabylovesyou · Answer

hartnn · Answer

same thing :)

hartnn · Answer

36 sqrt2 * k^3/2 =  36k sqrt(2k)

gabylovesyou · Answer

ok thanks :)

hartnn · Answer

welcome ^_^