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OpenStudy (gabylovesyou):
http://www.wolframalpha.com/input/?i=%288q%5E2%29+%2F+sqrt%28q%5E17%29+ @ParthKohli how do i check this answer? lol
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Parth (parthkohli):
Look at "alternate form assume q is positive"
OpenStudy (gabylovesyou):
but since its a fraction how do i simplify it more ?
Parth (parthkohli):
You cannot simplify fractions. And BTW, what answer do you get?
Parth (parthkohli):
You should have an answer for yourself before looking at one on Wolfram.
hartnn (hartnn):
\(\large \dfrac{8}{\sqrt{q^{13}}}, 8q^{-13/2}\)
are different forms of that same answer...
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Parth (parthkohli):
If you need help with it,\[\dfrac{8q^2}{\sqrt{q^{17}}} = \dfrac{8q^2}{q^{\frac{17}{2}}}\]
OpenStudy (gabylovesyou):
my answer was 8 sqrt(q) / (q^7)
hartnn (hartnn):
thats correct!
Parth (parthkohli):
Indeed.
hartnn (hartnn):
8/q^(13/2) = 8 sqrt(q) / (q^7)
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OpenStudy (gabylovesyou):
ok thanks :p
hartnn (hartnn):
same thing :)
hartnn (hartnn):
36 sqrt2 * k^3/2 = 36k sqrt(2k)
OpenStudy (gabylovesyou):
ok thanks :)
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hartnn (hartnn):
welcome ^_^
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