Suppose a runner takes 45 min to run a route a 8 mi/h at the beginning of training season. By the end of training season, she can run the same route in 38 min. What is her speed at the end of training season?
@amistre64 @mertsj @hartnn @Hero @ParthKohli @ivettef365
equate the distances, use Distance = Speed / Time
Her route's length is ...?
Well, 45/8=
5.6
so, speed1/ time1 = speed2/time2 time 1 = 45, speed1 = 8 time2 =38 find speed2, you will get that in mi/h
mi.
\[\dfrac{8 \rm ~miles}{\rm hour} \div 45 ~ \rm minutes\]
is the distance.
So multiply those 2? to reverse the equation?
no need to find distance...to get exact distance we have to do conversions...if we do the proportionality, we directly get speed in mi/hr
When you get the distance, you know that the runner covers the same distance.
45/8 = 35/x just find x
**38/x
x=6.2repeating
ooh 38..
45/38=1.18421526 8/1.18421526=6.755528551
So 6.8
yeah, thats her speed. in mi/h
45/38=1.2 8/1.2=6.6repeating
ok thnks all done...gee i havent gone to bed since like 7:00 am yesterday morning
:z
I need to catch some Zzzzzzzzzz's
-_- *snoring*
sleep well :) sweet dreams :)
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