HEEELLLPP! Q1: The product of five consecutive odd integers is 945. waht is the greatest possible value of any of these integers? Q2: a sequence of numbers begins with the numbers -10, 20, 30.... and each term afterward is the product of the precding three terms. How many of the first 101 terms of this sequence is positive? Q3: in how many ways can 2mango, 3 black berry and 3 tamarind trees can be planted in a straight line. if one does not distinguish between trees of the same kind. EXPLAIN IN THE EASIEST POSSIBLE WAY!
On Q1 just multiply 5 consecutive odd integers with answer 945 (1x3x5x7x9), what is the greatest value
how will we find out that which 5 consecutive odd integers we should use?
1. Let your first odd number be - 2n+1 (even +1 = odd) => 5 consecutive odd nos. = (2n+1)(2n+3)(2n+5)(2n+7)(2n+9)
@Aditi_Singh well i have to do this sum in a min, i don't think i can do all this calculation in 1 min :(. i tried and i got confused :(
To be honest, I got confused too :P I'm extremely sorry for the same :(
You know what? When you don't understand anything, start by taking examples. Like here, let's take the basic consecutive odd numbers - 1,3,5,7,9 here, 1x3x5x7x9 = 945 , thus, your answer would be 9 :P p.s : that's all i could think of :P
Let the middle no is x. then the no will be x-4, x-2, x, x+2, x+4. now product of these is x(x^2-4)(x^2-16) = 945, which is a cubic equation so analytically you can solve this and it leads to x = 5.
my line of thought for 1st, 945 hmm...its divisible by 5, so 189 189 is divisible by 3 (note : divisibility test for 2 to 5 are very easy) so, 189/3 = 63 and 63 easily is 9*7 so, 1,3,5,7,9 ...
Dude. 945 is also divisible by 3,15 and so many no..So I do not think this approach leads to a better way..:-) Because what no to take at first that always keeps importance..
ya ya , since last digit was 5, i attempted to divide it by 5...i never said its fullproof method :P
No issue hartnn..:-) Its also fine..:-)
@RahulKumar11 i actually did what @hartnn did but i wanted a formula type of stuff which is easy ! So thanks both of you :)
could you guys help me with the other two!
Heyyyyyyyyy
See term 1 = -ve, term 2 = +ve, term 3 = +ve, term4 -ve, term 5 = -ve..and so on..so if u exclude the first term u will get a pattern in which 50 terms will be positive and rest fifty term will be -ve..so total +ve term will be 51..:-)
hey @saifoo.khan @RahulKumar11 ah i see, but how did you get this idea ! i mean i won't be able to find out that whether i should drop the first term or not :/
in how many ways can 2mango, 3 black berry and 3 tamarind trees can be planted in a straight line. if one does not distinguish between trees of the same kind. 9!/(3!3!2!) n! = total ways that's 9. 3! bc there are 3 similar blackberries, 2! bc there are 2 similar mangoes and another 3! bc there are 3 similar tamarind. PS "similar" is the key here.
@saifoo.khan the options for the answers are a) 320, b)380 ,c)450 d) 560 ,e) 640 and what's up with this exclamation mark? what does it represent :@
Awesome tutorial here. https://www.khanacademy.org/math/probability/probability-and-combinatorics-topic/permutations_and_combinations/v/permutations
Which calc do you have Farheen?
so what about the options? does the answer lies in one of those?
in how many ways can 2mango, 3 black berry and 3 tamarind trees can be planted in a straight line. if one does not distinguish between trees of the same kind. 8!/(3!3!2!) n! = total ways that's 8. 3! bc there are 3 similar blackberries, 2! bc there are 2 similar mangoes and another 3! bc there are 3 similar tamarind. PS "similar" is the key here. It's d.
@saifoo.khan i am watching the video but if i don't get it you will be explaining me in detail ! Deal?
InshAllah.
@saifoo.khan i got what is in the video and i somewhat got what you wrote but they gave a formula which is n!/(n-k!). here n and k are similar. i mean we have total 8 ways and total 8 spots to fill and so this will give a 0 in the denominator. ab mein kya ghalat kar rahi hun explain karo?
@Farheen28...Sorry for keep delaying you. But rarely I use this site. If you have any query then you can post your message in my inbox of Facebook account, id is:- schonrahul@gmail.com
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