Mathematics
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OpenStudy (anonymous):
What is the simplified form of the expression
4c2 + 5c
4c2 + 7c
8c2 + 5c
8c2 + 7c
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OpenStudy (anonymous):
\[\sqrt{16c4} - \sqrt{c2} + 3 \sqrt{c2} + \sqrt{9c2}\]
ganeshie8 (ganeshie8):
nice latex !
ganeshie8 (ganeshie8):
simplify each term first
ganeshie8 (ganeshie8):
take first term :
\(\sqrt{16c^4}\)
OpenStudy (anonymous):
ok
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ganeshie8 (ganeshie8):
tell me this,
when u square, which number gives you \(16\) ?
OpenStudy (anonymous):
4 squred is 16
ganeshie8 (ganeshie8):
yes !
so when u take square root of 16, u wil get 4 back
ganeshie8 (ganeshie8):
\(\sqrt{16} = \sqrt{4^2} \)
= \( 4\)
ganeshie8 (ganeshie8):
the "square" and "square root" cancel out
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OpenStudy (anonymous):
ok
ganeshie8 (ganeshie8):
lets go back tofirst term :
\(\sqrt{16c^4}\)
\(\sqrt{4^2(c^2)^2}\)
\(4c^2\)
ganeshie8 (ganeshie8):
lets do the whole expression :-
OpenStudy (anonymous):
ok
ganeshie8 (ganeshie8):
\(\sqrt{16c4} - \sqrt{c2} + 3 \sqrt{c2} + \sqrt{9c2} \)
\( 4c^2 - c + 3 c+ 3c \)
simplify
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OpenStudy (anonymous):
The answer is 4c2 + 5c
OpenStudy (anonymous):
Whic is the first answer.
ganeshie8 (ganeshie8):
perfect !
OpenStudy (anonymous):
Thank you, you were awesome help.
ganeshie8 (ganeshie8):
np :)