Question

Find 4 consecutive odd integers where the product of the two smaller numbers is 64 less than the product of the two larger numbers. @mathstudent55

Answer 1

Let the smallest odd integer equal x.
How would you express the next larger one in terms of x?

Answer 2

idk

Answer 3

Look at the odd integer 5.
The next larger odd integer is 7.
If you start with 5, what operation would you do to get to 7?

Answer 4

7 is 2 more than 5. Any odd integer is 2 more than the previous one.

Answer 5

so whts the answer

Answer 6

If you let the smallest integer be represented by x, the next larger one is 2 more than x, or x + 2. Then the 3rd integer is 2 more than x + 2, or x + 2 + 2 which is x + 4. The largest of the integers is x + 6.
The 4 integers are x, x + 2, x + 4, x + 6
The problem states that the product of the two smaller ones, x(x + 2), is 64 less than the product of the two larger ones, (x + 4)(x + 6).
Now we can write an equation.

Answer 7

The equation is
x(x + 2) = (x + 4)(x + 6) - 64
Now you need to solve the equation to get x. That will give you smallest integer. Then add 2, 4, and 6, to x to get the other odd integers.

Answer 8

@shortie212
Here it is