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Mathematics 9 Online
OpenStudy (anonymous):

use substitution t=1/x to express limit as an equivalent limit in which for \[\lim_{x \rightarrow +\infty}\frac{ 6-x }{ 3+x }\]

OpenStudy (loser66):

i don't know why we have to substitute when we can calculate limit by itself?

OpenStudy (anonymous):

i also dont know why, but this is what my lecturer want me to do...lol

OpenStudy (loser66):

@Luigi0210

OpenStudy (dan815):

hey!! MY Friend

OpenStudy (loser66):

who?

OpenStudy (dan815):

lol u dummy!

OpenStudy (loser66):

ok, help him, please

OpenStudy (luigi0210):

Am I not your buddy dan? D:

OpenStudy (dan815):

hey so basically use the limit 1/x as x approaches 0

OpenStudy (loser66):

@Luigi0210 he is calling you, not me

OpenStudy (dan815):

from the right side, because that is the same as approaching +infinity

OpenStudy (dan815):

ofcourse u are!

OpenStudy (loser66):

why? since that limit =-1, why we have to substitute?

OpenStudy (dan815):

|dw:1370485063442:dw|

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