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use substitution t=1/x to express limit as an equivalent limit in which for \[\lim_{x \rightarrow +\infty}\frac{ 6-x }{ 3+x }\]
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i don't know why we have to substitute when we can calculate limit by itself?
i also dont know why, but this is what my lecturer want me to do...lol
@Luigi0210
hey!! MY Friend
who?
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lol u dummy!
ok, help him, please
Am I not your buddy dan? D:
hey so basically use the limit 1/x as x approaches 0
@Luigi0210 he is calling you, not me
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from the right side, because that is the same as approaching +infinity
ofcourse u are!
why? since that limit =-1, why we have to substitute?
|dw:1370485063442:dw|
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