Question

The midpoint of the segment joining points (a, b) and ( j, k) is:

Answer 1

here are some options

Answer 2

to find the mid point add the x's and div by 2
add the y's and div by 2

(a, b)
(j, K)
-----
a+j , k+b
--- ---
2 2

Answer 3

make sense?

Answer 4

ya thanks

Answer 5

yw

Answer 6

can you help with this one?

Answer 7

Point T is the midpoint of JH . The coordinate of T is (0, 4) and the coordinate of J is (0, 2). The coordinate of H is:

Answer 8

a.(0, 6)
b.(0, 3)
c.(0, 7)
d.(0, 11)

Answer 9

in this one the give you the mid point....so we need to do the opposite of before.

start with the mid point and instead of div by 2, mult by 2

(0, 4) * 2 = (0, 8 ) now subtract the other end
- (0, 2 )
-------
=

Answer 10

so it A right?

Answer 11

perfect!

Answer 12

what about this one Point (-4, 3) lies in Quadrant

a.I
b.II
c.III
d.IV

Answer 13

do you know how to graph the point?

Answer 14

ya

Answer 15

so its B

Answer 16

good!

Answer 17

Point (6, 0) lies on the

a.x-axis
b.y-axis
c.line y = x

Answer 18

it s x-axis right

Answer 19

???

Answer 20

right!
x y
(6, 0) over right 6, and zero up or down

Answer 21

what about this one?

Any line with no slope is parallel to the

a.x-axis
b.y-axis
c.line y = x

Answer 22

if it has no slope, that means it is flat... and horizontal line

which axis is horizontal?

Answer 23

X

Answer 24

right!

Answer 25

If the point (a,3) lies on the graph of the equation 5x + y = 8, then a=

a.1
b.-1
c.-7

Answer 26

they have given you a y
x y
(a, 3)

to find the other just sub in the 3 for y

5x + 3 = 8, now solve for x

Answer 27

x=1 right

Answer 28

great!

Answer 29

If the equation of a circle is (x + 5)^2 + (y - 7)^2 = 36, its center point is

a.(5, 7)
b.(-5, 7)
c.(5, -7)

Answer 30

in this take the opposite of each in the ( )'s

r = (-5, 7)

Answer 31

If the equation of a circle is (x + 5)^2 + (y - 7)^2 = 36, its radius is

a.6
b.16
c.36

Answer 32

take the sq root of what the equation = ____

Answer 33

i dont get it???

Answer 34

(x + 5)^2 + (y - 7)^2 = 36 it = 36, find the sq root of 36

Answer 35

sq root of 36 is 6 right

Answer 36

???

Answer 37

yes that is the radis

Answer 38

6

Answer 39

so 6 is the answer right?

Answer 40

yes,

Answer 41

If the equation of a circle is (x - 2)^2 + (y - 6)^2 = 4, the center is point (2, 6).

True
False

Answer 42

what do you think?

Answer 43

true

Answer 44

yep

Answer 45

it was nice helping you , but gotta run

Answer 46

okay thanks alot