Question

A rock is dropped from a height of 2.5 meters. What is its velocity when it reaches the ground?

Answer 1

You can approach this in a few different ways, but right now, I'll go with one off the top of my head. Here's a fundamental projectile motion equation:\[v ^{2} = v _{0}^{2}+2ax\]
Where V is your final velocity, Vo is your original velocity, a is your acceleration, and x is the total distance traveled. Now, since you know that it was dropped rather than thrown, you know that your starting (original) velocity is zero, yes? From here, you can just plug in and solve.

Answer 2

\[v ^{2} = (0) +2(2.5)(9.81)\]

Answer 3

49.05?

Answer 4

That would be v^2. Now what would v be, if what you have is v^2?

Answer 5

7

Answer 6

Yes! There you go. Do you understand now?

Answer 7

yess thank you :)