A bag has 7 red marbles, 8 blue marbles and 3 black marbles. What is the probability of picking a blue marble, replacing it, and then picking a red marble? Answers: 2/27 7/108 1/9 14/81
What do you know about basic probability?
not a lot @mrbarry
You do know that the probability of an event can be expressed as a ratio / fraction. The numerator is how many ways what you want could happen. The denominator is how many things could possible happen. Flip a coin. Probability of heads is 1/2. 1 way to get heads over 2 possibilities.
18 @mangorox
Now you know the denominator.
but thats not the denominator for the answer
@mrbarry that's not the denominator for the answer!
True, but it is part of finding the probability you need. How many ways can you get a blue marble?
dont know
How many blue marbles does the problem say there are?
8
So the probability of getting the blue marble on the first draw is: 8/18 which simplifies to....
4/9
Right. Now, what about the next part. You have put that blue marble back. What is the probability of now drawing a red?
1/9
?
# of reds = ------------------------ # of marbles=
and that is?
That fraction is the probability of getting a red from the full bag of marbles. There are 7 red marbles, so the probability should be....
7/108 right?
7/18 you mean?
right I was looking in the answer key
You just did two experiments. If we want to know the probability of one and then the other, we have to multiply the two probabilities together (4/9)(7/18) =
14/81 @mrbarry
Looks good!
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