f(1)=-5; f(2) = 7; f (3) = -6; f (n+3)=2f (n+2)-f(n+1)-3f(n). determine the first 5 terms of the sequence. can someone please help with this question :P
This is one is tougher to work, but we can do it. With sequences the only values of n we generally use are the numbers 1, 2, 3, 4, .... These are the natural or counting numbers. That being the case, if we substitute 1 for n the definitions says: f(4) = 2*f(3) - f(2) -3f(1) = f(5) = ?
ahh, i still dont seem to understand. i see what you did by subsituting 1 for n but i dont understand how to continue. the answer says that the first 5 terms are -5, 7,-6,-4,-23, if that helps :P
The problem gives us the first three terms as definitions. Check that out. Then.... f(4) = 2*f(3) - f(2) -3f(1) f(4) = (2*-6) - (7) - (3*-5) f(4) = (-12) - (7) - (-15) f(4) = -12 -7 + 15 f(4) = -4 f(5) = ? according to the pattern
oh!! 23!
But can you make it happen for yourself like I did with f(4)?
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