Question

If you are asked to find the infine geometric summation with k=1 but then you have a fract times another fraction enclosed with parenthesis to the power of a negative number how do you find it's intimating sumation?

Answer 1

Exactly what does it look like? ( / ) ( / )^?

Answer 2

Infinite Sumation K=1 1/5( 1/6)^-1

Answer 3

Someone please answer

Answer 4

I can help now that I see the problem more clearly.

\[\frac{ 1}{ 5 }(\frac{ 1 }{ 6 })^{-1}\]

Answer 5

That's the problems

Answer 6

k = 1 to infinity? Is there a k somewhere else like in the exponent?

Answer 7

K=1 is below the infine summation sign
E
k=1

Answer 8

Sorry n=1

Answer 9

There needs to a n somewhere in the formula. If we are looking at a geometric series, there should be a n in the exponent.

\[\sum_{n=1}^{\infty} \frac{ 1 }{ 5 }( \frac{ 1 }{ 6 })^{-1} = \frac{6}{5}\]

if there is no n somewhere.