Question

Find the area of an equilateral triangle with radius 5m. Leave your answer in simplest radical form. Rest in comments.

Answer 1

A. 225/4 \[\sqrt{3}\]
B. 45/4 \[\sqrt{3}\]
C. 75/2 \[\sqrt{3}\]
D. 15/2 \[\sqrt{3}\]

Answer 2

Now, I keep getting 25 sqrt (3)
I'm guessing the radius is from the center to the bottom like this

then, i would use the triangle area formula
a= 1/2 x b x h
a= 1/2 x 10 x 5 sqrt(3)
a= 5 x 5 sqrt(3)
a = 25 sqrt(3)

Answer 3

But that answer is none of the options... So, am I right or are one of the options actually the answer

Answer 4

whoops i messed up, "Find the area of an equilateral triangle with radius 5 sqrt(3)m. Leave your answer in simplest radical form. Rest in comments."

Answer 5

The area of an equilateral triangle can be found with the simple formula
\[\frac{ s ^{2}\sqrt{3} }{ 4 } \]
s= one side length, and since its equilateral, all sides are the same.
10^2 (sqt3)/4
100(sqt3)/4 - reduce
25sqt3

hmmmm, it appears you're right. i suppose A is a typo?

Answer 6

hum, i don't know... whats really getting me is what the heck is the radius of a triangle? i might be wrong by assuming its the center to the bottom, it actually might be the side... so

a= 5sqrt(3)^2 sqrt(3) / 4
a= 15sqrt(3) / 4
a = 15/4 sqrt(3)
but thts also none of the options

Answer 7

triangle has sides and angles. not radius and arcs.

Answer 8

exactly, so thats why i am so confused...

Answer 9

yeah must be question is incorrect. leave this question and move on... Also, call your teacher and inform :)

Answer 10

OK, thanks for trying to help, anyways. :) Thanks, everyone!

Answer 11

np :)