Question

Find cot60 degrees-sin45degrees

Answer 1

-0.20710678118

Answer 2

\[\cot 60-\sin 45=\frac{\cos 60}{\sin 60}-\frac{\sqrt2}2=\frac{\frac12}{\frac{\sqrt3}2}-\frac{\sqrt2}2=\frac1{\sqrt3}-\frac{\sqrt2}2=\frac{2-\sqrt6}{2\sqrt3}\]

Answer 3

Its suppose to be one of these answers
a.)thats for responding but the 4 answers are a)2-sqrt3/2
b.)2 square root3-3 square root 2/6
c)2-squareroot2/2
d)2 square root 2-3 square root 3/6

Answer 4

OK ! We can complete from the last solution :
\[\cot 60-\sin 45=\frac{2-\sqrt6}{2\sqrt3}=\frac{2\sqrt3-3\sqrt2}{6}\]