Question

Find 4 consecutive odd integers where the product of the two smaller numbers is 64 less than the product of the two larger numbers. @alli14344 @mathstudent55

Answer 1

Well I just finished it on your "now closed" question...go have a look And I cannot just give you answers

Answer 2

Did it at least make sense this time @shortie212 ?

Answer 3

A way to guarantee that a number will be odd is to call it
2n+1
Odd integers skip every other number, so I can
call them
2n+1, 2n+3, 2n+5, 2n+7
given:
(2n+1)*(2n+3) = (2n+5)*(2n+7)-64
4n^2+8n+3=4n^2+24n+35-64
8n+3=24n-29
16n=32
n=2

Answer 4

one sec..

Answer 5

and ...
2n+1=5
2n+3=7
2n+5=9
2n+7=11
the numbers are 5, 7, 9 , and 11
.....

CHECK:

5*7=9*11-64
35=99-64
35=35
ok :)

Answer 6

k