secx*cscx= 2secx how can I find the solution?
essentially: ab = 2a
ab = 2a ab-2a = 0 a (b-2) = 0
\[\sec x \csc x -2\sec x=0\] \[\sec x \left( \csc x-2 \right)=0\] now you can solve it.
or, since secx is never zero ab = 2a b = 2 1/b = 1/2
Alrighty,I have one solution but i don't know if there is others
well, pi/6 and 5pi/6 seem to work for me
\[1/\cos(x)•1/\sin(x)=2/\cos(x)\] Multiplying by cos(x), \[\cos(x)•1/\cos(x)•1/\sin(x)=\cos(x)•2•1/\cos(x)\] \[1/\sin(x)=2\] Multiplying by sin(x), \[\sin(x)•1/\sin(x)=2•\sin(x)\] \[1=2\sin(x)\] \[\sin(x)=1/2\] \[π/6+2πn, 5\pi/6+2πn\] (or, if you need it in degrees, 30º+n360º and 150º+n360º)
|dw:1370546711917:dw|
would 11pi/6 be one too?
no
oh okay
but essentially, its all turns that get you into pi/6 and 5pi/6
1,13,25,... +12 each time 5,17,29,... +12 each time 11 aint there
because sin x is positive ,it has to be in first and second quadrant only.
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