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Chemistry 10 Online
OpenStudy (anonymous):

A 23.0-g sample of water is put into a calorimeter and heated until its temperature increases from 31.0°C to 68.0°C. If the specific heat of water is 4.18 J/(g°C), calculate the heat absorbed by water. (Answer format: 1234.567 J, there is a space between # and J)

OpenStudy (anonymous):

can anyone help???

OpenStudy (aaronq):

q=mCdT ps. dT is the change in temp, so dT=T2-T1 you're solving for heat, q.

OpenStudy (anonymous):

be careful with units

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