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Sin(arcsec(x))
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So, I have already done the algebra for this problem, and I get sqrt(x^2-1)/x. My question is, why do some books put an absolute value on the x?
The put the abs value bars on the x in the denominator, why?
*they
If you look at this page http://www.intmath.com/analytic-trigonometry/7-inverse-trigo-functions.php you'll see that the range of arcsecant is 0 < y < pi so essentially the domain of sin(x) in this case is 0 < x < pi since arcsec(x) is the input of the sine function. This is why sine is always positive so they're forcing x to be positive when they stick those absolute value bars around it
Your explanation made a lot of sense, thank you
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