if 20.0 mL of CO2 gas at 1.00 atm is allowed to expand until the pressure is 0.830 atm what would be the new volume? ( temperature is held constant)

Question

abb0t · Answer

$P_1V_1 = P_2V_2$  where P = pressure [atm] and V = volume [L] 

NOTE: you must use your tools from algebra to rearrange the formula and solve for $V_2$

anonymous · Answer

wait so how is its set up with the formula

abb0t · Answer

divide by $P_2$

anonymous · Answer

divide what im confused

abb0t · Answer

divide by $P_2$ the second pressure!
$P_1$ = initial pressure
$V_1$ = initial volume 
$P_2$ = change in pressure 
$V_2$ = new volume

You have: $P_1V_1 = P_2V_2$ SO DIVIDE by $P_2$ so that you can volse for $V_2$

anonymous · Answer

yeah i understood that but how do i set the equation up with the problem ?

abb0t · Answer

Uh... $\huge V_2 = \frac{P_1V_1}{P_2}$

anonymous · Answer

no its ok nvm

abb0t · Answer

ok. Lol

anonymous · Answer

so the answer is 20.4