-3x-12=-3(x+4)
distribute the right
-3x-12=-3-12
now finish
do I have add 12 to both sides?
\[\large \large -3x-12=-3(x+4) \] You want to solve for x. So you first want to distribute first. (To make equation easier). So let's see, 3(x+4). How to distribute it... Break it down into factor. It should look like -3 times x + -3 times 4. That would give you -3x - 4. So your equation should look like: \[\large \large -3x - 12 = -3x -12\] Next step is to reverse PEMDAS. So let see, let's get rid of -12! To get rid of -12, you want to add it by 12, to cancel it. -12 + 12 = 0 (Cancel out) -12 + 12 = 0 (Cancel out) Your equation should now look like: \[\large \large -3x = -3x\] This is easy. Final step is to divide both side by -3. -3 divided by -3 is 1. -3 divided by -3 is 1. So x =1
I hope this help!
if you divide by -3 doesn't that leave you with x=x?
Personally, I don't understand what you're asking. As far as I can see, "-3x-12=-3(x+4)" is simply "true".
1x = 1x.
Oh, so it's either: x = 1 Or the equation is true.
thanks for help I understand much better :)
Wait nevermind. x can be any number, if there are identical.
or it's 0=0
So x can be 9000! Or 1, 5, 10. There's an infinit solution.
my other question is similar 24y-2(6-y)=6(3y+2)
I got 24y-12y-2y=18y+12?
\[\large \large 24y-2(6-y)=6(3y+2)\] After doing to distribute property, your equation should end up like: \[\large \large 24y - 12 - 2y = 18y +18\] So you are so far correct.
Opps. My bad. 18y + 12. You are still correct.
24y-2(6-y) = 6(3y+2) First expand the parenthetical terms: 24y-12+2y = 18y+12 Combine terms: 26y-12 = 18y+12 Now rearrange the furniture: 26y-18y = 12+12 Simplify: 8y = 24 Dividing both sides by 8 yields: y = 3
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