Find the exact values of the six trigometric functions of theta if theta is in standard positiion and the terminal side of theta is quadrant 4 and is on the line y=-3/7x

Question

mertsj · Answer

|dw:1370569132874:dw|

anonymous · Answer

k then this would be square root 58 and then how would i ifind the 6 trigometric functions?

mertsj · Answer

$$\sin x=\frac{side opp}{hypotenuse}$$

mertsj · Answer

Use the definitions.

anonymous · Answer

but why do we use sin?

mertsj · Answer

What does the problem ask you to find?

anonymous · Answer

Find the exact values of the six trigometric functions of theta if theta is in standard positiion and the terminal side of theta is quadrant 4 and is on the line y=-3/7x

mertsj · Answer

So, the problem says to find the values of the 6 trig functions.  What are the 6 trig functions?

anonymous · Answer

this is what i got 

sin theta =y/r=-3/sqrt 58
cos theta=x/r=7/sqrt58
tan=y/x=-3/7
csc theta=r/y=sqrt 58/3
sec=r/x=sqrt58/7
cot=x/y =-7/3

mertsj · Answer

csc should be negative.  You should rationalize the denominators

anonymous · Answer

$$\sqrt{58\frac{ }{ ? }} \times\frac{ 3 }{ 3 }$$

anonymous · Answer

sqrt58 divided by 3

mertsj · Answer

sqrt58/3

mertsj · Answer

Denominator is already rational.

anonymous · Answer

i dont get why u say its a negative(csc theta).sorry for all the questions im trying to understand

mertsj · Answer

Because the csc is the reciprocal of the sin and the sin (which is like y) is negative in Quadrant IV

anonymous · Answer

so its sqrt 58 divided by -3?