Mathematics
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OpenStudy (anonymous):
Evaluate the Intergal
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OpenStudy (anonymous):
\[\int\limits_{}^{}\frac{ 1 }{ \sqrt{e^x-1} }\]
OpenStudy (anonymous):
I can't do u sub, trig sub partial fraction or Integration by parts :/ . How would I even approach this?
sam (.sam.):
Try u-sub where
\[u=e^x \\ \\ du=e^xdx \\ \\ \frac{du}{e^x}=dx\]
\[\int\limits \frac{1}{\sqrt{u-1}}\frac{du}{e^x}\]
\[\int\limits \frac{1}{\sqrt{u-1}(u)}du\]
OpenStudy (anonymous):
Umm okay.
sam (.sam.):
You mean you're not allowed to use u-sub?
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OpenStudy (anonymous):
I am :P .
sam (.sam.):
ok
OpenStudy (anonymous):
Just thinking about afterwards.
OpenStudy (anonymous):
I see a parts Integration but I don't think that's the best way.
OpenStudy (anonymous):
Could I use Partial Fractions?
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OpenStudy (zarkon):
I would let \(u=\sqrt{e^x-1}\)
OpenStudy (anonymous):
Why so? I was thinking abut that as well.
OpenStudy (anonymous):
but I noticed that it's derivative isn't in the Intergal.
OpenStudy (zarkon):
\[\Rightarrow e^x=u^2+1\]
OpenStudy (anonymous):
Okay I see it. What about the DIfferential dx though?
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OpenStudy (zarkon):
\[du=\frac{1}{2\sqrt{e^x-1}}e^xdx\]
OpenStudy (anonymous):
Ohh!
OpenStudy (anonymous):
Nice one!
OpenStudy (zarkon):
\[\frac{2u}{u^2+1}du=dx\]
OpenStudy (anonymous):
How did you come up with that? :P .
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OpenStudy (zarkon):
I've done a lot of integrals
OpenStudy (anonymous):
I plan on doing that as well :) .
OpenStudy (anonymous):
Thanks!