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Mathematics 15 Online
OpenStudy (anonymous):

Evaluate the Intergal

OpenStudy (anonymous):

\[\int\limits_{}^{}\frac{ 1 }{ \sqrt{e^x-1} }\]

OpenStudy (anonymous):

I can't do u sub, trig sub partial fraction or Integration by parts :/ . How would I even approach this?

sam (.sam.):

Try u-sub where \[u=e^x \\ \\ du=e^xdx \\ \\ \frac{du}{e^x}=dx\] \[\int\limits \frac{1}{\sqrt{u-1}}\frac{du}{e^x}\] \[\int\limits \frac{1}{\sqrt{u-1}(u)}du\]

OpenStudy (anonymous):

Umm okay.

sam (.sam.):

You mean you're not allowed to use u-sub?

OpenStudy (anonymous):

I am :P .

sam (.sam.):

ok

OpenStudy (anonymous):

Just thinking about afterwards.

OpenStudy (anonymous):

I see a parts Integration but I don't think that's the best way.

OpenStudy (anonymous):

Could I use Partial Fractions?

OpenStudy (zarkon):

I would let \(u=\sqrt{e^x-1}\)

OpenStudy (anonymous):

Why so? I was thinking abut that as well.

OpenStudy (anonymous):

but I noticed that it's derivative isn't in the Intergal.

OpenStudy (zarkon):

\[\Rightarrow e^x=u^2+1\]

OpenStudy (anonymous):

Okay I see it. What about the DIfferential dx though?

OpenStudy (zarkon):

\[du=\frac{1}{2\sqrt{e^x-1}}e^xdx\]

OpenStudy (anonymous):

Ohh!

OpenStudy (anonymous):

Nice one!

OpenStudy (zarkon):

\[\frac{2u}{u^2+1}du=dx\]

OpenStudy (anonymous):

How did you come up with that? :P .

OpenStudy (zarkon):

I've done a lot of integrals

OpenStudy (anonymous):

I plan on doing that as well :) .

OpenStudy (anonymous):

Thanks!

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