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Mathematics 19 Online
OpenStudy (anonymous):

Please help me?? How many times larger is the new volume of a cylinder if only the height doubled, and the radius remained the same?

OpenStudy (anonymous):

i think it is 2x bigger?

OpenStudy (anonymous):

@dan815

OpenStudy (whpalmer4):

You have a 3-dimensional object, and you only changed one dimension, right? That means the new volume is simply the old volume * the scale factor.

OpenStudy (whpalmer4):

If the height stayed the same, but the radius doubled, what would happen to the volume?

OpenStudy (anonymous):

gets bigger

OpenStudy (whpalmer4):

well, yes. how much :-)

OpenStudy (anonymous):

2x

OpenStudy (anonymous):

so i am right?

OpenStudy (whpalmer4):

mmm, no. Think of it this way: the volume of the cylinder is the height time the area of the base, right? The area of the base is proportional to the radius squared, right?

OpenStudy (whpalmer4):

So if you double the height, the new V is the area of the base * 2*times the old height, so new V = area of base * old height * 2 which is old volume * 2

OpenStudy (anonymous):

4?

OpenStudy (whpalmer4):

bingo!

OpenStudy (anonymous):

thanks!

OpenStudy (whpalmer4):

you have to apply the scale factor to as many dimensions as changed. If you have a line, and you double the length, the length is doubled, duh. If you have a square and double one dimension, the area doubles. If you doubled both dimensions, then it is 2*2 = 4. If you doubled one dimension and tripled the other it would be 2*3 = 6. in 3 D, you have 3 dimensions to keep track of, like the cylinder base is a 2 d thing (circle) so when the radius doubles, it is 2*2 in addition to whatever happened to the height.

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