What is significant about e?
|dw:1370591523328:dw|
\[\dfrac{\partial}{\partial x} a^x = a^x \log_e a \]The fact that the natural log and not any other log base comes up is very interesting.
\(Ce^x\) is the only function with a constant derivative.
it is its own derivative!
I don't think constant derivative is the right way to say it...
you cant do differential equations without it:)
\[e^{I*\pi} + 1 = 0\]
That's another way to say it lol \(1\) is its own square, cube and its own square root, cube root. \(e^x\) is its own second, third derivative and is its own second, third integral. So if \(1\) is the king of arithmetic, then \(e^x\) is the king of the functions!
lol hah that is great
e was the first letter in Eulers name!
I can do this all day
lol
there are many significant, its irrational. ^^I hope someone gets that
we are nerds Parth
:)
And it's the real compounding: the continuous compounding. If you keep 1 dollar in a bank and it keeps compounding 1% at each instant, then the amount in the bank after \(1\) year will be \(e\).
The longer the instant, the more you are more way off \(e\)
\(e\) is also transcendental. :-D
I with I could give you another medal:P
lol
e^it = cost + isint
now simplify
That one too!
\[e^{i\pi}=1\]
that's the same thing, hes repeating:P
it = it
\[e^{2i\pi}=-1\]
omfg can someone tell goformit100 to stop asking stupid questions
this one is cooler, it has the first prime, addition, multiplication,exponential....
\[e^x = 1 + x + \dfrac{x^2}{2} + \dfrac{x^3}{6} + \cdots\]
\[e^{2\pi i} + 1 = 0\]:-D
and thus we know \[\int\limits e^{x^{2}}dx\]
You can solve that using alternative numbering systems
there are many ways, but the coolest is expansion imo
x^x^x^x^x? I had to do that back when I was a freshman in math 55 LOL
Take the derivative of it..took like an hour
lol
no ty
Join our real-time social learning platform and learn together with your friends!