Question

differentiate f(x)=secx/1+tanx

Answer 1

Is this what you're given?\[f(x)=\frac{ \sec(x) }{ 1+\tan(x) }\]

Answer 2

What you have written would actually be\[f(x)=\sec(x)+\tan(x)\]

Answer 3

its a quotient, thus commands application of quotion rule in my view

Answer 4

I haven't taken a derivative, I'm merely trying to clarify what the original problem is.

Answer 5

its a quotient, consider your first correction not the second

Answer 6

Ah, okay, so just plug in your values for quotient rule where\[\frac{ f(x) }{ g(x) }=\frac{ f'(x)g(x)-f(x)g'(x) }{ (g(x))^{2} }\]

Answer 7

...?

Answer 8

i bet brenar has a point there,

Answer 9

here What you have written would actually be
f(x)=sec(x)+tan(x)
that 's yours

Answer 10

\[\large \frac{d}{dx}[\frac{\sec(x)}{1+\tan(x)}]\]\[\large f'(x) = \frac{d}{dx}(\sec x) = \sec(x)\tan(x)\]\[\large g'(x) = \frac{d}{dx}[\tan(x)] =\sec^2(x)\]

Answer 11

@Loser66 I wrote that because @falzedu had the wrong notation in his original equation, I merely wanted to clarify, because I knew what he had most likely intended. It's an order of operations thing.

Answer 12

Can you solve it now? lol

Answer 13

just use the quotient rule, Goodness.

Answer 14

haha @Jhannybean

Answer 15

@Brenar got it, but I don't think there is something wrong with the question. quotient rule, done

Answer 16

\[\large \frac{[\sec(x)\tan(x)]*(1+\tan(x)) - \sec^2(x)[\sec(x)]}{[1+\tan(x)]^{2}}\]

Answer 17

That is ILLEGAL

Answer 18

Because that's not what he wrote, he wrote f(x)=secx/1+tanx which is the same as\[f(x)=\sec(x)+\tan(x)\]

Answer 19

Just... calm down and use quotient rule.

Answer 20

Stop being so knit-picky. He just forgot the parenthesis. Lol

f(x) = (sec(x))/(1+tan(x))

Answer 21

@Jhannybean I know, but I don't believe @Loser66 understood that.

Answer 22

I always thought it was "nit-picky"
But yeah, @Jhannybean 's right, the power of LaTeX wasn't used so pick the more probable question :D

Answer 23

lol KNITTING AND PICKING!

Answer 24

post a new post friend