two large horizontal metal plates are separated by 4mm. the lower plate isat a potential of -6v. what potential should be applied to the upper plate to create filed strength of 4000v/m upwards in the space between the plates

Question

anonymous · Answer

Since E field is upwards ,therefore upper plate is at lower potential than the lower plate..
Let the potential of upper plate is V.

Magnitude of potential difference between the plates = -4-V

E = (-4-V) / 4 mm
Put the given value of E and find V.

anonymous · Answer

Sorry, it is -6 instead of -4

anonymous · Answer

thanks but what i got was -10. am i correct?

anonymous · Answer

Wait, it should be -22. 
With -10 ,we will get only 1000V/m electric field.

anonymous · Answer

thank u sir